Exploring the Connection: The Link between De Broglie Wavelength and Crompton Wavelength

N.K Sahoo
2 min readJan 16, 2023

To find out the relationship between the De.broglie Wavelength (λd) and Crompton wavelength (λc), first we need to understand their proper meaning.

When a material particle is associated with a wave is called Mater Wave and is associated with a wavelength is called De.broglie Wavelength(λd).

i.e λ = h/p = h/mv (since p=mv)

The λd can be considered in 2 cases viz. Relativistic (K.E of particle >> Rest mass Energy) and Non-relativistic (K.E of particle << Rest mass Energy). But, Relativistic case is more general in De.broglie wavelength. i.e

E = √(p²c²+m•²c⁴)

E² = p²c²+m•²c⁴

p²c²= E²- m•²c⁴

p²c²= E²- E•²

Thus,

λd = hc/pc = hc/√(E²- E•²)— — — (1)

But, according to Einstein, we have
m = γm• = m•/√(1-v²/c²) &

E = γE• = E•/√(1-v²/c²)

Now,

λd = hc/√(E²-E•²)

λd = hc/√{E•²(γ²-1)}

λd = hc/m•c {1/γ²-1}

λd = λc {1/γ²-1} — — — (2)

Where, λc = Crompton wavelength

[ we know,

γ²-1 = 1/(1-v²/c²)-1

or γ²-1 = v²/c²-v² ]

λd = λc {c²-v²/v²} — — — (3)

Equation (3) represents the relationship between Crompton wavelength and De.broglie wavelength.

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N.K Sahoo

Physicst, Tech Enthusiast & Content writer. Primarily focused on making content on Science, Engineering, puzzles, fun facts & more. Hope you like.